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URL to title

Simple program that reads an url and prints the last part of the path as a title.

Code

from urllib.parse import urlparse

def get_last_path(url:str) -> str:
    # Parse the URL
    parsed_url = urlparse(url)

    # Get the path from the parsed URL
    path = parsed_url.path

    # Split the path by slashes and get the last part
    path_parts = path.split('/')
    last_part = path_parts[-1]

    return last_part

def path_to_title(path:str) -> str:
    return path.replace("-", " ").title()

def main():
    url = input("Enter the URL: ")
    path = get_last_path(url)
    title = path_to_title(path)
    print(title)

if __name__ == "__main__":
    while True:
        try:
            main()
        except KeyboardInterrupt:
            break

Case of use

I use this to format references in my mardown documents. For example, given the url 

https://stackoverflow.com/questions/76392847/flutter-firebase-to-python-firebase

The program outputs

Flutter Firebas To Python Firebase

which I use to link to the question, like so:

[Flutter Firebas To Python Firebase](https://stackoverflow.com/questions/76392847/flutter-firebase-to-python-firebase)

References